The correct order of acid strength for the following carboxylic acids is:

I > I I I > I I > I V

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I I I > I I > I > I V

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I > I I > I I I > I V

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I I > I > I V > I I I

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Solution

The correct option is C $I > I I > I I I > I V$

Stronger will be the acid when its conjugate base is highly stabilised. (I) is the most acidic and (IV) is the least since $C O_{2}^{-}$ group is attached with a $s p$ hybridised carbon in (I) and with a $s p^{3}$ hybridised carbon in (IV).
(III) is less acidic than (II) as the electron donating group ( $- O M e$ ) destabilises the carboxylate anion by increasing the electron density in the ring.
Hence the order is: $I > I I > I I I > I V$

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Similar questions

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

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C_{6} H_{5} C O O H

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(iv)

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