The correct order of activation of benzene ring towards an electrophile is :

(IV)>(III)>(II)>(I)

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(III)>(I)>(IV)>(II)

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(III)>(IV)>(I)>(II)

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(IV)>(III)>(II)>(I)

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Solution

The correct option is C (III)>(IV)>(I)>(II)
$(I I I) > (I V) > (I) > (I I)$
The trend is on the basis of resonance of functional groups with benzene ring. $O C H_{3}, O = O, - O C O C H_{3}$ are electron donating groups and fluorine is an electron withdrawing group.

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