The correct order of atomic size of $C, N, P, S$ follows the order

$N < C < S < P$

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$N < C < P < S$

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$C < N < S < P$

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$C < N < P < S$

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Solution

The correct option is A
$N < C < S < P$

$I V V V I$

$C N$

$P S$

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Similar questions

The correct order of atomic size of $C, N, P, S$ follows the order

The correct order of atomic size of $C, N, P, S$ is

N, F, S i

P

K^{+}, C l^{-}, S^{2 -}, C a^{2 +}

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