The correct order of basicities of the following compounds is

2 > 1 > 3 > 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 > 3 > 2 > 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 > 1 > 2 > 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 > 2 > 3 > 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 > 1 > 3 > 4$
The correct order is 2>1>3>4
Because oh the ethyl amine is most basic than amide and 2 degree amine

Suggest Corrections

Similar questions

Q. Arrange in decreasing order of basicity:

Q. Arrange the following in the order of decreasing basic character:
1. p-Toluidine
2. N,N-Dimethyl-p-toludine
3. p-Nitroaniline
4. Aniline

Q. The correct reactivity order of following C = C /

C \equiv

C bonds towards

B r^{\oplus}

is:

Q. The correct order of basicity of the following compounds is?

(C H_{3})_{4} N H (3)

C H_{3} C O N H_{2} (4)

Question 22

Which of the following is an example of distributive property of multiplication over addition for rational numbers.
(a) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [- \frac{1}{4} \times \frac{2}{3}] + [- \frac{1}{4} \times (\frac{- 4}{7})]$
(b) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [\frac{1}{4} \times \frac{2}{3}] - (\frac{- 4}{7})$
(c) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = \frac{2}{3} + (- \frac{1}{4}) \times \frac{- 4}{7}$
(d) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = {\frac{2}{3} + (\frac{- 4}{7})} - \frac{1}{4}$

Join BYJU'S Learning Program

The correct order of basicities of the following compounds is

The correct option is A 2>1>3>4The correct order is 2>1>3>4Because oh the ethyl amine is most basic than amide and 2 degree amine

The correct option is A $2 > 1 > 3 > 4$
The correct order is 2>1>3>4
Because oh the ethyl amine is most basic than amide and 2 degree amine