Question

The correct order of basicity of the following compounds is:

• A. $1<2<3<4$
• B. $1<2<4<3$
• C. $2<1<3<4$
• D. $4<3<2<1$

Answer 1

The correct option is C $2<1<3<4$

The correct order of basicity is:

$2<1<3<4$

The basic strength order depends on:
(i) Accumulation of negative charge on $N$ (double bonded) by another $-N{H}_2$group, thus intensifying the donor ability of $N$.

(ii) The higher donor ability of $s{p}^3$ hybrid $N$ as compared to $s{p}^{2}N$.

Option C is correct.