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Phthalimide Reaction

The correct o...

Question

The correct order of boiling point of hydrides of nitrogen family is

PH₃< ASH₃< NH₃< SbH₃

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NH₃< PH₃< ASH₃< SbH₃

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NH₃< SbH₃< PH₃< AsH₃

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SbH₃< PH₃< AsH₃< NH₃

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Solution

The correct option is A
PH₃< ASH₃< NH₃< SbH₃

Due to H bonding in ammonia

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

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