The correct order of boiling points for the given halides is:

C C l_{4} < C H_{3} C l < C H_{2} C l_{2} < C H C l_{3}

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C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l < C C l_{4} <

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C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

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C H_{3} C l < C H_{2} C l_{2} < C H C l_{3} < C C l_{4}

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Solution

The correct option is D $C H_{3} C l < C H_{2} C l_{2} < C H C l_{3} < C C l_{4}$
Intermolecular forces of attractions increases as molecular mass increases. So, large amount of heat require to break strong intermolecular forces and thus boiling point increases.
Here, the order of molecular mass is as follows : $C H_{3} C l < C H_{2} C l_{2} < C H C l_{3} < C C l_{4}$ and thus boiling point also increases in same order.
$C H_{3} C l < C H_{2} C l_{2} < C H C l_{3} < C C l_{4} .$

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