The correct order of C - H bond length in CH 3- CH 3- CH 2- CH 2 and CH - CH is-A- CH 3- CH 3- CH 2- CH 2- CH - CHB- CH 2- CH 2- CH 3- CH 3- CH - CHC- CH - CH - CH 2- CH 2- CH 3- CH 3D- all are equal

The correct option is C CH ≡ CH lt; CH_2 = CH_2 lt; CH_3 CH_3C H bond length in the shown order are based on sp, sp^2 and sp^3 hybridisations. nbsp ...

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Standard XII

Chemistry

Physical Properties of Alkynes

The correct o...

Question

The correct order of C - H bond length in $C H_{3} - C H_{3}, C H_{2} = C H_{2}$ and $C H \equiv C H$ is:

C H_{3} - C H_{3} < C H_{2} = C H_{2} < C H \equiv C H

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C H_{2} = C H_{2} < C H_{3} - C H_{3} < C H \equiv C H

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C H \equiv C H < C H_{2} = C H_{2} < C H_{3} - C H_{3}

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all are equal

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Solution

The correct option is C $C H \equiv C H < C H_{2} = C H_{2} < C H_{3} - C H_{3}$
$C - H$ bond length in the shown order are based on $s p, s p^{2}$ and $s p^{3}$ hybridisations. $s p^{3}$ has the highest bond length followed by $s p^{2}$ and $s p$ . So, the correct answer is option (c).

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Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

and

C H \equiv C H

is:

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Physical Properties of Alkynes

Standard XII Chemistry

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The correct order of C - H bond length in CH3−CH3,CH2=CH2 and CH≡CH is:

The correct option is C CH≡CH<CH2=CH2<CH3−CH3C−H bond length in the shown order are based on sp,sp2 and sp3 hybridisations. sp3 has the highest bond length followed by sp2 and sp. So, the correct answer is option (c).

The correct order of C - H bond length in $C H_{3} - C H_{3}, C H_{2} = C H_{2}$ and $C H \equiv C H$ is:

The correct option is C $C H \equiv C H < C H_{2} = C H_{2} < C H_{3} - C H_{3}$
$C - H$ bond length in the shown order are based on $s p, s p^{2}$ and $s p^{3}$ hybridisations. $s p^{3}$ has the highest bond length followed by $s p^{2}$ and $s p$ . So, the correct answer is option (c).