The correct order of decreasing bond length of $C = C$ in the above compounds is:

I I > I > I V > I I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I I I > I I > I > I V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I V > I I > I > I I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $I I > I > I V > I I I$
The bond length of $C = C$ is affected by presence or absence of electron pushing group like $- C H_{3}$ . Presence of methyl groups decrease the electron deficiency and the length of double bond thus increases. Similarly, presence of more double bonds has more electron attracting tendency of the bonds, due to which more double bonds cause shorter $C = C$ .
Hence the decreasing bond length of $C = C$ will be:
$I I > I > I V > I I I$

Suggest Corrections

Similar questions

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

Q. Arrange the following compounds in decreasing order of their reactivity with sodium methoxide in methanol at

50^{\circ}

Q. Consider the following phenols

The decreasing order of acidic nature of the above phenols is :

The decreasing nucleophilic order of the following compound is:

$(i) Θ C H_{3}$

$(i i) Θ N H_{2}$

$(i i i) Θ O H$

$(i v) Θ F$

Q. The decreasing order of priority for the following functional groups is
I.

- C \equiv N

II.

- C O N H_{2}

III.

IV.

- N H_{2}

Join BYJU'S Learning Program

The correct order of decreasing bond length of C=C in the above compounds is:

The correct order of decreasing bond length of $C = C$ in the above compounds is: