The correct order of decreasing electronegativity values among the elements I-beryllium II-oxygen, III-nitrogen and IV-magnesium is :

II > III > I > IV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

III > IV > II > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I > II > III > IV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I > II > IV > III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

II > III > IV > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A II > III > I > IV
Electronegativity increases along a period and decreases in a group. Thus, the order is (II) > (III) > (I) > (IV). Electronegativity of 0- 3. 5, N -3.0, Be -1. 5, Mg -1.2 .

Suggest Corrections

Similar questions

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

- I

- C N

- N O_{2}

- N H_{2}

- F

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

The correct order for decreasing stability of the following free radicals is

P h O^{⊖}

C H_{3} S^{⊖}

⊖ O H

M e O^{⊖}

Join BYJU'S Learning Program