Question

The correct order of decreasing polarisability of ion is :

• A. $C{l}^{-}>B{r}^{-}>I^{-}>F^{-}$
• B. $F^{-}>I^{-}>B{r}^{-}>C{l}^{-}$
• C. $I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$
• D. $F^{-}>C{l}^{-}>B{r}^{-}>I^{-}$

Answer 1

The correct option is C $I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$

The polarisability of an anion also depends on its size and charge – the larger the negative ion and the larger its charge the more polarisable it becomes, that is, more is the size of anion more will be the polarisability.