The correct order of $E_{M^{2 +} / M}^{0}$ values with a negative sign for the four successive elements Cr, Mn, Fe and Co is:

Fe > Mn > Cr > Co

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Cr > Mn > Fe > Co

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Mn > Cr > Fe > Co

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Cr > Fe > Mn > Co

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Solution

The correct option is C Mn > Cr > Fe > Co
Usually across the first transition series, the negative values for standard electrode potential decrease except for Mn due to stable d5-configuration.

The electronic configuration of various elements in Mn $^{2 +}$ state is:
Cr- [Ar] 3d $^{4}$
Mn-Cr- [Ar] 3d $^{5}$ -half filled- most stable.
Fe-Cr- [Ar] 3d $^{6}$
Co-Cr- [Ar] 3d $^{7}$

So, based on above facts the correct order is:

Mn> Cr> Fe> Co.

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Similar questions

E^{0} M^{2 +} / M

For the four successive transition elements (Cr, Mn, Fe and Co), what is the order of stability of their +2 states?

(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

E_{M^{2 +} / M}^{o}

C r, M n, F e

C o

E^{0} M^{2 +} / M

E_{M^{2 +} / M}

C r

M n

F e

C o

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