The correct order of electron density in the aromatic ring of the above compounds is :

I V > I I I > I I > I

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I > I I > I I I > I V

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I V > I I > I > I I I

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I V > I I > I I I > I

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Solution

The correct option is B $I V > I I > I I I > I$
The electron density in the aromatic ring will increase with the presence of electron donating group as a substituent.

The order of electron donating power of the substituents given is: $- N H C O C H_{3} > - O C O E t > - C H_{3} > - C O O E t$ .

The order is based on the resonance effect of the substituents.

Option D is correct.

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