1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Multi-Electron Configurations and Orbital Diagrams
The correct o...
Question
The correct order of energy difference between adjacent energy levels in H atom :
A
E
2
−
E
1
>
E
3
−
E
2
>
E
4
−
E
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
E
2
−
E
1
>
E
4
−
E
3
>
E
3
−
E
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
E
4
−
E
3
>
E
3
−
E
2
>
E
2
−
E
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
E
3
−
E
2
>
E
4
−
E
3
>
E
2
−
E
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
E
2
−
E
1
>
E
3
−
E
2
>
E
4
−
E
3
En
ergy value of
E
1
= 13.6 ev
En
ergy value of
E
2
= 3.4ev
En
ergy value of
E
3
= 1.51 ev
En
ergy value of
E
4
= 0.85 ev
So
E
2
−
E
1
=
10.2
E
3
−
E
2
=
1.89
E
4
−
E
3
=
0.66
and 10.2 > 1.89 >0.66
So that
E
2
−
E
1
>
E
3
−
E
2
>
E
4
−
E
3
i
s correct order.
Suggest Corrections
0
Similar questions
Q.
If
E
1
,
E
2
,
E
3
a
n
d
E
4
are the energies required to knock off the
1
s
t
,
2
n
d
,
3
r
d
and
4
t
h
electrons respectively from outermost orbit of the Carbon atom, choose the correct option:
Q.
If
E
1
,
E
2
,
E
3
a
n
d
E
4
are the energies required to knock off the 1st, 2nd, 3rd and 4th electron respectively from the outermost orbit of the Carbon atom, choose the correct option:
Q.
If
E
1
,
E
2
,
E
3
a
n
d
E
4
are the energies required to knock off the
1
s
t
,
2
n
d
,
3
r
d
a
n
d
4
t
h
electrons (from the last shell) respectively from outermost orbit of the Carbon atom, choose the correct option:
Q.
If
E
=
E
1
E
2
E
3
E
4
E
5
and
P
(
E
1
)
=
95
100
,
P
(
E
2
/
E
1
)
=
94
99
,
P
(
E
1
/
E
1
E
2
)
=
93
98
,
P
(
E
4
/
E
1
E
2
E
3
)
=
92
97
and
P
(
E
5
/
E
1
E
2
E
3
E
4
)
=
91
96
, then find
P
(
E
)
.
Q.
If
E
=
E
1
∩
E
2
∩
E
3
∩
E
4
∩
E
5
and
P
(
E
1
)
=
95
100
,
P
(
E
2
/
E
1
)
=
94
99
,
P
(
E
3
/
(
E
1
∩
E
2
)
)
=
93
98
,
P
(
E
4
/
E
1
∩
E
2
∩
E
3
)
=
92
97
and
P
(
E
5
/
E
1
∩
E
2
∩
E
3
∩
E
4
)
=
91
96
, then
P
(
E
)
is:
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Electronic Configuration and Orbital Diagrams
CHEMISTRY
Watch in App
Explore more
Multi-Electron Configurations and Orbital Diagrams
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app