The correct order of energy of 2s orbitals in H, Li, Na and K, is
A
K < Na < Li < H
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B
Na < Li < K < H
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C
Na < K < H < Li
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D
H < Na < Li < K
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Solution
The correct option is A K < Na < Li < H As we go down the group IA, there is increase in the number of shells so size of atom increases and energy of 2s orbital decreases.