The correct order of enthalpy of vaporisation of noble gases is :

H e < N e < A r < K r < X e

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H e > N e > A r > K r > X e

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H e < A r < K r < N e < X e

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H e < X e < A r < N e < K r

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Solution

The correct option is B $H e < N e < A r < K r < X e$
Enthalpy of vaporization $α$ Van der Waals forces $α$ Molar mass
Thus, as molar mass increases, the enthalpy of vaporization increases.
Thus correct order of enthalpy of vapourisation of noble gases
$X e > K r > A r > N e > H e$

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X e > K r > A r > N e > H e

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