The correct order of equivalent conductance at infinite dilution in water at room temperature for $H^{+}, K^{+}, {C H}_{3} C O O^{-}$ and ${H O}^{-}$ ions is :

{H O}^{-} > H^{+} > K^{+} > {C H}_{3} C O O^{-}

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H^{+} > {H O}^{-} > K^{+} > {C H}_{3} C O O^{-}

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H^{+} > K^{+} > {H O}^{-} > {C H}_{3} C O O^{-}

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H^{+} > K^{+} > {C H}_{3} C O O^{-} > {H O}^{-}

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Solution

The correct option is B $H^{+} > {H O}^{-} > K^{+} > {C H}_{3} C O O^{-}$

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Similar questions

H O^{⊖}

{C H}_{3} C O O^{⊖}

{{C H}_{3} C O O}^{-}

H O^{-}

The structure of D-(+)-mannose is:

The structure of L-(–)-mannose is:

(H O^{-}, C H_{3} C O O^{-}, P h O^{-}, C H_{3} O^{-}) .

C H_{3} C O O H + O H^{-} ⇋ C H_{3} C O O^{-} + H_{2} O + q_{1}

H^{+} + O H^{-} ⇋ H_{2} O + q_{2}

C H_{3} C O O H ⇋ C H_{3} C O O^{-} + H^{+}

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