Question

The correct order of equivalent conductances at infinite dilution of $LiCl,NaCl$ and $KCl$ is:

• A. $LiCl>NaCl>KCl$
• B. $KCl>NaCl>LiCl$
• C. $NaCl>KCl>LiCl$
• D. $LiCl>KCl>NaCl$

Answer 1

The correct option is B $KCl>NaCl>LiCl$

Since the anions are same so we will compare the size of cations.

$\therefore$ $L{i}^{+}$ < $N{a}^{+}$ < $K^{+}$.

But due to hydration of cation, the order of radii becomes

$L{i}^{+}$ >$N{a}^{+}$ >$K^{+}$

We know that,

$Conductance$ $\alpha$ $\frac{1}{radii}$

$\therefore$ The order becomes $KCl$ > $NaCl$ > $LiCl$

Hence the correct option is 'C'.