Question

The correct order of equivalent conductivity at infinite dilution of $LiCl,NaCl$ and $KCl$ is:

• A. $LiCl>NaCl>KCl$
• B. $KCl>NaCl>LiCl$
• C. $NaCl>KCl>LiCl$
• D. $LiCl>KCl>NaCl$

Answer 1

Answer: (B)

$KCl>NaCl>LiCl$

The correct order of equivalent conductivity at infinite dilution of $LiCl,NaCl$ and $KCl$ is $KCl>NaCl>LiCl$.

Ionic mobility depends upon size of the ion. The ionic size in case of hydrated cation, is $K^{+}\left(aq\right)<N{a}^{+}\left(aq\right)<L{i}^{+}\left(aq\right)$.

As the size of the hydrated ion increases, the equivalent conductivity at infinite dilution decreases.