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Question

The correct order of hybridization of the central atom in the following species is:

NH3,[PtCl4]2,PCl5 and BCl3

A
dsp2,dsp3sp2,sp3
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B
sp3,dsp2,dsp3,sp2
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C
dsp2,sp2,sp3,dsp3
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D
dsp2,sp3,sp2,dsp3
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Solution

The correct option is B sp3,dsp2,dsp3,sp2
NH3,[PtCl4]2,PCl5 and BCl3 have sp3,dsp2,sp3d and sp2-hybridization respectively. Note that hybridization of P in PCl5 is wrongly reported in the problem.
Hybridization in NH3 :It is is sp3 because N is bonded to 3 hydrogen groups and contains two unpaired electrons. For these three bonds and unpaired electron, the s orbital and three p orbitals hybridize forming sp3 hybridized orbitals.

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