Question

The correct order of hybridization of the central atom in the following species $N{H}_3,[PtC{l}_4{]}^{2-},PC{l}_5$ and $BC{l}_3$ is:

• A. $ds{p}^2,ds{p}^3,s{p}^2,s{p}^3$
• B. $s{p}^3,ds{p}^2,s{p}^{3}d,s{p}^2$
• C. $ds{p}^2,s{p}^2,s{p}^3,ds{p}^3$
• D. $ds{p}^2,s{p}^3,s{p}^2,ds{p}^3$

Answer 1

The correct option is B $s{p}^3,ds{p}^2,s{p}^{3}d,s{p}^2$

In $NH3$, $N$ is $s{p}^3$ hybridised

In $[PtCl4{]}^{2-}$, $Pt$ is $ds{p}^2$ hybridised

In $PC{l}_5$, $P$ is $s{p}^{3}d$ hybridised

In $BC{l}_3$, $B$ is $s{p}^2$ hybridised