The correct order of hydrated radius is:

L i^{+} (a q) < B e^{2 +} (a q)

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N a^{+} (a q) < A l^{3 +} (a q)

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I^{-} (a q) > C l^{-} (a q)

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B a^{2 +} (a q) < C a^{2 +} (a q)

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Solution

The correct options are
A $L i^{+} (a q) < B e^{2 +} (a q)$
B $N a^{+} (a q) < A l^{3 +} (a q)$
D $B a^{2 +} (a q) < C a^{2 +} (a q)$
Radius comprises of ion and closely bound water molecules is hydrated radius. Hydrated radius depends upon charge density. Ion with smaller size and high charge has greater radius of hydration whereas ion with bigger in size and low charge has smaller radius of hydration.

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