The correct order of increasing acidic nature of $S O_{2}, S i O_{2}, P_{2} O_{3}$ and $A l_{2} O_{3}$ is :

S O_{2} < P_{2} O_{3} < S i O_{2} < A l_{2} O_{3}

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A l_{2} O_{3} < S i O_{2} < S O_{2} < P_{2} O_{3}

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A l_{2} O_{3} < S i O_{2} < P_{2} O_{3} < S O_{2}

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S i O_{2} < S O_{2} < A l_{2} O_{3} < P_{2} O_{3}

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Solution

The correct option is C $A l_{2} O_{3} < S i O_{2} < P_{2} O_{3} < S O_{2}$
As oxidation number of central atom increases, acidity of its oxide increases. Also, on moving along a period acidic strength increase, Hence the correct order is,
$A l_{2} O_{3} < S i O_{2} < P_{2} O_{3} < S O_{2}$
+3 +4 +3 +4

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