The correct order of increasing atomic size of element $N, F, S i$ & $P$ is:

N < F < S i < P

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F < N < P < S i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F < N < S i < P

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N < S i < F < P

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $F < N < P < S i$
Atomic Size in a period decreases from left to right and decreases in a group from top to bottom.
So, Order is $F < N < P < S i .$
Option B is correct

Suggest Corrections

Similar questions

Q. Considering the elements B, C, N, F and Si the correct order of their
non-metallic character is:

(a)

B > C > S i > N > F

(b)

S i > C > B > N > F

(c)

F > N > C > B > S i

(d)

F > N > C > S i > B

Considering the elements B, C, N, F, and Si, the correct order of their non-metallic character is:
(a) B > C > Si > N > F
b) Si > C > B > N > F
(c) F > N > C > B > Si
d) F > N > C > Si > B

Q. Which of the following order are correct with respect to the strength of XX single

σ

covalent bonds?
(p)

S i - S i < G e - G e

(q)

N - N < P - P

(r)

C l - C l > F - F

(s)

O - O < S - S

Q. Arrange the following elements in the increasing order of their metallic character.

S i, B e, M g, N a, P

Q. Atomic radius(pm) of

A l, S i, N

and

F

respectively is:

Join BYJU'S Learning Program

The correct order of increasing atomic size of element N,F,Si & P is:

The correct option is A F<N<P<SiAtomic Size in a period decreases from left to right and decreases in a group from top to bottom.So, Order is F<N<P<Si.Option B is correct

The correct order of increasing atomic size of element $N, F, S i$ & $P$ is:

The correct option is A $F < N < P < S i$
Atomic Size in a period decreases from left to right and decreases in a group from top to bottom.
So, Order is $F < N < P < S i .$
Option B is correct