The correct order of increasing basic nature for the bases $N H_{3}, C H_{3} N H_{2}$ and $(C H_{3})_{2} N H$ is?

(C H_{3})_{2} N H < N H_{3} < C H_{3} N H_{2}

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N H_{3} < C H_{3} N H_{2} < (C H 3)_{2} N H

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C H_{3} N H_{2} < (C H_{3})_{2} N H < N H_{3}

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C H_{3} N H_{2} < N H_{3} < (C H_{3})_{2} N H

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Solution

The correct option is B $N H_{3} < C H_{3} N H_{2} < (C H 3)_{2} N H$
$(H_{3} C)_{2} N H$ , $C H_{3} N H_{2}$ , $N H_{3}$
Among the above molecules $(C H_{3})_{2} N H$ is most basic as two electron donating group are attached to it which increase its basicity is
$N H_{3} < C H_{3} N H_{2} < (C H_{3})_{2} N H$

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