The correct order of increasing electronegativity is:

C < O < S i

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N < O < F

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C < O < N

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B < O < C

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Solution

The correct option is B $N < O < F$
The electronegativity increases along the period. It also decreases along the group. Thus considering theses $2$ trends, the correct order of electronegativity is $N < O < F$

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The van der waals radii of $O, N, C l, F$ and $N e$ increases in the order of:

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

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