The correct order of increasing number of alpha particles passing undeflected through the foils of $A u, A g, C u$ and $A l$ of $1000$ atoms thickness each in a simulated alpha particle scattering experiment of Rutherford would be:

A u < A g < C u < A l

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A l < C u < A g < A u

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A u < C u < A l < A g

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A g < C u < A l < A u

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Solution

The correct option is A $A u < A g < C u < A l$
More the atomic number (nuclear charge), more will be the deflection. Thus, in gold number of undeflected particles will be smallest. Hence, $A u < A g < C u < A l$ is correct.

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