Question

The correct order of increasing percentage s character in the hybrid orbitals in the given molecules/ions is: (assume all hybrid orbitals are equivalent)
$\begin{array}{ccccc}C{O}_3^{2-}& Xe{F}_4& I_3^{-}& NC{l}_3& BeC{l}_2\\ \left(I\right)& \left(II\right)& \left(III\right)& \left(IV\right)& \left(V\right)\end{array}$

• A. II < III < IV < I < V
• B. II < IV < III < V < I
• C. III < II < I < V < IV
• D. II < IV < III < I < V

Answer 1

The correct option is A II < III < IV < I < V

$C{O}_3^{2-}=s{p}^{2}NC{l}_3=s{p}^3$
$Xe{F}_4=s{p}^3{d}^{2}BeC{l}_2=sp$
$I_3^{-}=s{p}^{3}d$

$s{p}^2,\%s=\frac{1}{3}\times 100s{p}^3{d}^2,\%s=\frac{1}{6}\times 100s{p}^{3}d,\%s=\frac{1}{5}\times 100s{p}^3,\%s=\frac{1}{4}\times 100sp,\%s=\frac{1}{2}\times 100$