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Question

The correct order of increasing percentage s character in the hybrid orbitals in the given molecules/ions is: (assume all hybrid orbitals are equivalent)
CO23XeF4I3NCl3BeCl2(I)(II)(III)(IV)(V)
  1. III < II < I < V < IV
  2. II < III < IV < I < V
  3. II < IV < III < I < V
  4. II < IV < III < V < I


Solution

The correct option is B II < III < IV < I < V
CO23=sp2         NCl3=sp3
XeF4=sp3d2   BeCl2=sp
I3=sp3d

sp2, %s = 13×100sp3d2, %s = 16×100sp3d, %s = 15×100sp3, %s = 14×100sp, %s = 12×100

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