The correct order of increasing radii of the elements Na, Si, Al and P is :

Si, Al, P, Na

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Al, Si, P, Na

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P, Si, Al, Na

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Al, P, Si, Na

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Solution

The correct option is B P, Si, Al, Na
It is known that on moving down the group, the ionic radii increases and on moving across the period from left to right, ionic radii decreases.
Here, biggest element would be $N a$ then $A l$ followed by $S i$ and $P$ . $P$ is the smallest element among these.
$N a M g A l S i P - ----------------- \to$
ionic radii $↓↓$
Hence, $P < S i < A l < N a$

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Similar questions

The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
(a) Na< Mg > Al < Si (b) Na> Mg > Al > Si
(c) Na< Mg< Al< Si (d) Na> Mg> Al < Si

Question 17
Arrange the following elements in the order of their decreasing metallic character
Na, Si, Cl, Mg, Al

(a) Cl > Si >Al > Mg >Na
(b) Na >Mg >Al >Si > Cl
(c) Na > Al > Mg > Cl > Si
(d) Al > Na> Si > Ca> Mg

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

Q. The first ionisation energies of six

3^{r d}

period elements are 496, 578, 738, 789, 1000 and 1012

{kJ mol}^{- 1}

. The elements to which these energies correspond respectively are:

N a^{+}

M g^{2 +}

A l^{3 +}

and

S i^{4 +}

are isoelectronic, their ionic size will follow the order:

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