Question

The correct order of ionic radii for the ions, $P^{3-},S^{2-},C{a}^{2+},K^{+},C{l}^{-}$ is

• A. $K^{+}>C{a}^{2+}>P^{3-}>S^{2-}>C{l}^{-}$
• B. $P^{3-}>S^{2-}>C{l}^{-}>C{a}^{2+}>K^{+}$
• C. $P^{3-}>S^{2-}>C{l}^{-}>K^{+}>C{a}^{2+}$
• D. $C{l}^{-}>S^{2-}>P^{3-}>C{a}^{2+}>K^{+}$

Answer 1

The correct option is C $P^{3-}>S^{2-}>C{l}^{-}>K^{+}>C{a}^{2+}$

For isoelectronic species, as nuclear charge increases radius decreases.

Greater the positive charge, lesser the size of ion. Greater the negative charge, larger the size of ion.

$\therefore$ $P^{3-}>S^{2-}>C{l}^{-}>K^{+}>C{a}^{2+}$