The correct order of ionic radii of Ce, La, Pm, and Yb in +3 oxidation state is:

L a^{3 +} < P m^{3 +} < C e^{3 +} < Y b^{3 +}

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Y b^{3 +} < P m^{3 +} < C e^{3 +} < L a^{3 +}

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L a^{3 +} < C e^{3 +} < P m^{3 +} < Y b^{3 +}

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Y b^{3 +} < C e^{3 +} < P m^{3 +} < L a^{3 +}

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Solution

The correct option is C $L a^{3 +} < C e^{3 +} < P m^{3 +} < Y b^{3 +}$
${L a}^{3 +} > {C e}^{3 +} > {P m}^{3 +} > {Y b}^{3 +}$

Due to lanthanoid contraction ionic radii decreases.
Ionic radii decreases from $L a^{3 +} - L u^{3 +}$ in +3 oxidation state.

Hence, the correct option is $C$ .

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