The correct order of ionic radii of $Y^{3 +}, {L a}^{3 +}, {E u}^{3 +}$ and ${L u}^{3 +}$ is:

{L u}^{3 +} < {E u}^{3 +} < {L a}^{3 +} < Y^{3 +}

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{L a}^{3 +} < {E u}^{3 +} < {L u}^{3 +} < Y^{3 +}

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Y^{3 +} < {L a}^{3 +} < {E u}^{3 +} < {L u}^{3 +}

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Y^{3 +} < {L u}^{3 +} < {E u}^{3 +} < {L a}^{3 +}

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Solution

The correct option is C $Y^{3 +} < {L u}^{3 +} < {E u}^{3 +} < {L a}^{3 +}$
The correct order is $Y^{3 +} < {L u}^{3 +} < {E u}^{3 +} < {L a}^{3 +}$ because $E u$ and $L u$ are members of lanthanides series and $L a$ is such series and $Y^{3 +}$ ion has lower radii as compared to ${L a}^{3 +}$ because it lies immediately above ${L a}^{3 +}$ in periodic table.
So, The correct answer is(D)
$Y^{3 +} < {L u}^{3 +} < {E u}^{3 +} < {L a}^{3 +}$

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