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Question
The correct order of Ka is:
(i) CH3−CH2−COOH
(ii) OHC−CH3−COOH
(iii) C6H5−CH2−COOH
The correct order of Ka is:
(i) CH3−CH2−COOH
(ii) OHC−CH3−COOH
(iii) C6H5−CH2−COOH
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Solution
The correct option is C ii > iii > i
Electron withdrawing group increase the acidity of carboxylic acid by withdrawing electron making O−H bond more polar. As a result H+ ion can be easily removed.
3-Oxopropanoic acid (OHC−CH2−COOH) is strong acid than phenylacetic acid (C6H5−CH2−COOH) and acetic acid (CH3−CH2−COOH) due to presence of electron withdrawing group.
Phenylacetic acid is more acidic than acetic acid thus the acidic strength order is ii > iii > i.
More the acidic strength, more is Ka value.
Electron withdrawing group increase the acidity of carboxylic acid by withdrawing electron making O−H bond more polar. As a result H+ ion can be easily removed.
3-Oxopropanoic acid (OHC−CH2−COOH) is strong acid than phenylacetic acid (C6H5−CH2−COOH) and acetic acid (CH3−CH2−COOH) due to presence of electron withdrawing group.
Phenylacetic acid is more acidic than acetic acid thus the acidic strength order is ii > iii > i.
More the acidic strength, more is Ka value.
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