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Question

The correct order of Ka is?
(i) CH3−CH2−COOH
(ii) OHC−CH2−COOH
(iii) C6H5−CH2−COOH

A
iii > ii > i
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B
i > ii > iii
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C
ii > iii > i
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D
i > iii > ii
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Solution

The correct option is C ii > iii > i
Electron withdrawing group increase the acidity of carboxylic acid by withdrawing electron making OH bond more polar. As a result, H+ ion can be easily removed.

3-oxopropanoic acid (OHCCH2COOH) is strong acid than phenylacetic acid (C6H5CH2COOH) and acetic acid (CH3CH2COOH) due to presence of electron withdrawing group (CHO).
Phenylacetic acid is more acid than acetic acid thus the acidic strength order is ii > iii > i.
more the acidic strength more is Ka value of acid. Hence the Ka value order is ii > iii > i.

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