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The correct o...

Question

The correct order of magnetic moments (spin only values in B.M.) among the complexes is:

{[F e {(C N)}_{6}]}_{6}^{4 -} > {[M n C l_{4}]}_{4}^{2} > {[C o C l_{4}]}_{4}^{2 -}

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{[M n C l_{4}]}_{4}^{2 -} > [F e {(C N)}_{6}]^{4 -} > {[C o C l_{4}]}_{4}^{2 -}

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{[M n C l_{4}]}_{4}^{2 -} > {[C o C l_{4}]}_{4}^{2 -} > {[F e {(C N)}_{6}]}_{6}^{4 -}

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{[F e {(C N)}_{6}]}_{6}^{4 -} > {[C o C l_{4}]}_{4}^{2 -} > {[M n C l_{4}]}_{4}^{2 -}

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Solution

The correct option is C ${[M n C l_{4}]}_{4}^{2 -} > {[C o C l_{4}]}_{4}^{2 -} > {[F e {(C N)}_{6}]}_{6}^{4 -}$
$C l^{-}$ is a weak ligand while $C N^{-}$ is a strong ligand.
In $[M n C l_{4}]^{2} : d^{5}$ configuration and 5 unpaired electrons
In $[C o C l_{4}]^{2} : d^{7}$ configuration and 3 unpaired electrons
In $[F e (C N)_{6}]^{4} : d^{6}$ configuration, low spin complex and 0 unpaired electrons
More the number of unpaired electrons, more the value of magnetic moment. Hence, the order is ${[M n C l_{4}]}_{4}^{2 -} > {[C o C l_{4}]}_{4}^{2 -} > {[F e {(C N)}_{6}]}_{6}^{4 -}$

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M n = 25; F e = 26; C o = 27

18

[C u (N H_{3})_{4}]^{2 +}, [C u (e n)_{3}]^{2 +}, [C u (C N)_{4}]^{3 -}

[F e (C N)_{6}]^{4 -}, [F e (C N)_{6}]^{3 -}, F e (C O)_{6}

[N i (N H_{3})_{6}]^{2 +}, [N i (C N)_{4}]^{2 -}, [N i (C O)_{4}]

[C r (N H_{3})_{6}]^{3 +}, [C r (C O)_{6}]

[C o (N H_{3})_{6}]^{3 +}, [C o C l_{4}]^{2 -}

(I) [C r (H_{2} O)_{6}] B r_{2}

(I I) N a_{4} [F e (C N)_{6}]

(I I I) N a_{3} [F e (C_{2} O_{4})_{3}] (Δ_{0} > P)

(I V) (E t_{4} N)_{2} [C o C l_{4}]

[V (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{4 -}

[R u (N H_{3})_{6}]^{3 +}

[C r (N H_{3})_{6}]^{2 +}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[N i (C N)_{4}]^{2 -}

[N i (H_{2} O)_{4}]^{2 +}

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