The correct order of magnetic moments (spin values in $B M$ ) among is

[F e (C N)_{6}]^{4 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -}

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[M n C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -} > [C o C l_{4}]^{2 -}

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[F e (C N)_{6}]^{4 -} > [M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -}

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[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}

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Solution

The correct option is C $[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$
The number of unpaired electrons in the compounds $[M n C l_{4}]^{2 -}, [C o C l_{4}]^{2 -} a n d [F e (C N)_{6}]^{4 -}$ are 5,3 and 0 respectively.
As the number of unpaired electrons increases, the magnetic moment values also increases.
Hence, the correct order of magnetic moments (spin values in BM) among is $[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$ .

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M n = 25; F e = 26; C o = 27

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[C u (N H_{3})_{4}]^{2 +}, [C u (e n)_{3}]^{2 +}, [C u (C N)_{4}]^{3 -}

[F e (C N)_{6}]^{4 -}, [F e (C N)_{6}]^{3 -}, F e (C O)_{6}

[N i (N H_{3})_{6}]^{2 +}, [N i (C N)_{4}]^{2 -}, [N i (C O)_{4}]

[C r (N H_{3})_{6}]^{3 +}, [C r (C O)_{6}]

[C o (N H_{3})_{6}]^{3 +}, [C o C l_{4}]^{2 -}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[N i (C N)_{4}]^{2 -}

[N i (H_{2} O)_{4}]^{2 +}

(I) [C r (H_{2} O)_{6}] B r_{2}

(I I) N a_{4} [F e (C N)_{6}]

(I I I) N a_{3} [F e (C_{2} O_{4})_{3}] (Δ_{0} > P)

(I V) (E t_{4} N)_{2} [C o C l_{4}]

Magnetic moment of $[M n C l_{4}]^{2 -}$ is 5.92 BM. Explain giving reason present.

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