The correct order of $N -$ compounds in its decreasing order of oxidation states is:

H N O_{3}, N H_{4} C l, N O, N_{2}

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H N O_{3}, N O, N_{2}, N H_{4} C l

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N H_{4} C l, N_{2}, N O, H N O_{3}

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H N O_{3}, N O, N H_{4} C l, N_{2}

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Solution

The correct option is B $H N O_{3}, N O, N_{2}, N H_{4} C l$
Oxidation state of $N$ in $H N O_{3} = + 5$
Oxidation state of $N$ in $N O = + 2$
Oxidation state of $N$ in $N_{2} = 0$
Oxidation state of $N$ in $N H_{4} C l = - 3$

Hence, the correct option is $B$

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