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Liquefaction of Gases and Critical Constants

The correct o...

Question

The correct order of normal boiling points of $O_{2}, N_{2}, N H_{3}$ and $C H_{4}$ for whom the values of van der Waal's constant 'a' are $1.360, 1.390, 4.170$ and $2.253$ $L^{2}$ atm mol $^{- 2}$ respectively, is :

A

O_{2} < N_{2} < N H_{3} < C H_{4}

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B

O_{2} < N_{2} < C H_{4} < N H_{3}

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C

N H_{3} < C H_{4} < N_{2} < O_{2}

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D

N H_{3} < C H_{4} < O_{2} < N_{2}

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Solution

The correct option is B $O_{2} < N_{2} < C H_{4} < N H_{3}$
van der Waal's constant 'a' depicts the correction of intermolecular forces. Higher the value of 'a' stronger the intermolecular force.
The order of normal boiling points : $O_{2} < N_{2} < C H_{4} < N H_{3}$ .

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Q. The correct order of normal boiling points of

O_{2}, N_{2}, N H_{3}

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for whom the values of van der Waal's constant

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\begin{matrix} Gas & a (L^{2} a t m m o l^{- 2}) N_{2} & 1.390 O_{2} & 1.360 N H_{3} & 4.170 C H_{4} & 2.253 \end{matrix}

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