The correct order of polarisation power of cation is:

N a^{+} > M g^{2 +}

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L i^{+} < N a^{+}

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N a^{+} < C u^{+}

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Z n^{2 +} > H g^{2 +}

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Solution

The correct option is B $N a^{+} < C u^{+}$
Polarization power of $C u^{+}$ is more than $N a^{+}$ . Because $C u^{+}$ ion is smaller than $N a^{+}$ ion of and thus the charge density of $C u^{+}$ ion is greater than $N a^{+}$ ion resulting in more polarizing power.

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Similar questions

{N a}^{+}, {C a}^{2 +}, {M g}^{2 +}, {A l}^{3 +}

{C a}^{2 +} < {N a}^{+} < {M g}^{2 +} < {A l}^{3 +}

F^{-}, O^{2 -}, N a^{+}, M g^{2 +}

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

L i^{+}

N a^{+}

C s^{+}

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