The correct order of pseudohalide,polyhalide and interhalogen are

B r I_{2}^{-}, O C N^{-}, I F_{5}

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I F_{5} . B r I_{2}^{-}, O C N^{-}

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O C N^{-}, I F_{5}, B r I_{2}^{-}

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O C N^{-}, B r I_{2}^{-}, I F_{5}

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Solution

The correct option is D $O C N^{-}, B r I_{2}^{-}, I F_{5}$
Interhalogen are the compound of two halogens.
So $I F_{5}$ is interhalogen.
$O C N^{-}$ acts as halide but actually is not a halide .
So, $O C N^{-}$ is pseudo halide

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If \frac{5}{8} \times \frac{4}{3} \times \frac{2}{3} = A, compare the value of A with 1

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