The correct order of radii is

N < Be < B

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F^{-} < O^{2 -} < N^{3 -}

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Na < Li < K

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F e^{3 +} < F e^{2 +} < F e^{4 +}

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Solution

The correct option is B $F^{-} < O^{2 -} < N^{3 -}$
Among isolectronic species, greater the negative charge, greater the ionic size, hence $F^{-} < O^{2 -} < N^{3 -}$

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The correct order of radii is

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