The correct order of radii is

Be> N>B

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$N^{3 ⊖} > O^{2 ⊖} > F^{⊖}$

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Na>Li>K

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$F e^{+ +} > F e^{3 +} > F e^{2 +}$

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Solution

The correct option is B
$N^{3 ⊖} > O^{2 ⊖} > F^{⊖}$

The correct order of radii is
$N^{3 -} > O^{2 -} > F^{-}$

All these three species are isoelectronic. Just check the number of protons pulling the electrons.

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Similar questions

F e

F e^{2 +}

F e^{3 +}

F^{-}, O^{2 -}, N a^{+}, M g^{2 +}

The correct order of ionic radii of the species $N^{3 -}, O^{2 -}, N a^{+}$ and $F^{-}$ is:

N a^{+}, M g^{2 +}, F^{-}

O^{2 -}

F^{-}, O^{2 -}, N a^{+}, M g^{2 +}

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