The correct order of rate of $S_{N} 2$ reactivity of $H_{2} O, ¯ O H, C H_{3} C O ¯ O, P h - O^{-}$ is:

P h - O^{-} > ¯ O H > C H_{3} C O ¯ O > H_{2} O

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H_{2} O > ¯ O H > C H_{3} C O ¯ O > P h - O^{-}

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¯ O H > P h - O^{-} > C H_{3} C O ¯ O > H_{2} O

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H_{2} O > P h - O^{-} > C H_{3} C O ¯ O > ¯ O H

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Solution

The correct option is A $P h - O^{-} > ¯ O H > C H_{3} C O ¯ O > H_{2} O$
$S N^{2}$ reactivity $α$ Nuecleophicity
$\Rightarrow P h - O^{-} > - O H > C H_{3} C O O^{-} > H_{2} O$

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Similar questions

1

M

N a H C O_{3}

H_{2} C O_{3} + H_{2} O ⇌ H C O_{3}^{-} + H_{3} O^{+};

p K_{1} = 6.38

H C O_{3}^{-} + H_{2} O ⇌ C O_{3}^{2 -} + H_{3} O^{+};

p K_{2} = 10.26

⊖ S H, A C ⊖ O, P h ⊖ O, ⊖ O H, H_{2} O

H_{2} O + H_{3} {P O}_{4} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{-}; p K_{1} = 2.15

H_{2} O + H_{2} {P O}_{4}^{-} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{2 -}; p K_{2} = 7.20

0.01 M

N a H_{2} {P O}_{4}

⊖ S H, A C ⊖ O, P h ⊖ O, ⊖ O H, H_{2} O

P h - C l M g - ---- \to dry ether C O_{2} / H^{+}, H_{2} O - -------- \to S O C l_{2} - --- \to i . C H_{2} N_{2} - ------- \to i i . A g_{2} O, H_{2} O

O

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