The correct order of rate of $S_{N} 2$ reactivity of $H_{2} O, C H_{3} O^{-}, O H^{-}, C H_{3} C O O^{-}$ is:

O H^{-} > C H_{3} O^{-} > C H_{3} C O O^{-} > H_{2} O

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H_{2} O > O H^{-} > C H_{3} O^{-} > C H_{3} C O O^{-}

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C H_{3} O^{-} > O H^{-} > C H_{3} C O O^{-} > H_{2} O

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H_{2} O > C H_{3} C O O^{-} > O H^{-} > C H_{3} O^{-}

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Solution

The correct option is C $C H_{3} O^{-} > O H^{-} > C H_{3} C O O^{-} > H_{2} O$
This is $S_{N} 2$ reaction and it proceeds through transition state formation.
So, its rate depends upon, both concentration of alkyl halide and nucleophile. So, stronger the nucleophile is, faster the reaction.
Among all given electrophiles, $C H_{3} O^{-}$ is the strongest due to the absence of resonance.
The strength order of nucleophile is $C H_{3} O^{-} > O H^{-} > C H_{3} C O O^{-} > H_{2} O .$
So, the reactivity order is $C H_{3} O^{-} > O H^{-} > C H_{3} C O O^{-} > H_{2} O$ .

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Similar questions

{S_{N}}^{2}

H_{2} O

^{-} O C H_{3},^{-} O H

C H_{3} C O O^{-}

Arrange in decreasing order of basicity,

$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

{S_{N}}^{2}

H_{2} O

^{-} O C H_{3},^{-} O H

C H_{3} C O O^{-}

C H_{3} C O O H + O H^{-} ⇋ C H_{3} C O O^{-} + H_{2} O + q_{1}

H^{+} + O H^{-} ⇋ H_{2} O + q_{2}

C H_{3} C O O H ⇋ C H_{3} C O O^{-} + H^{+}

C H_{3} C O O H + O H^{-} \to C H_{3} C O O^{-} + H_{2} O + q_{1}

H^{+} + O H^{-} \to H_{2} O + q_{2}

C H_{3} C O O H \to C H_{3} C O O^{-} + H^{+}

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