The correct order of reactivity among I (atomic hydrogen), II (dihydrogen) and III (nascent hydrogen) is:

I > I I > I I I

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I > I I I > I I

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I I > I I I > I

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I I I > I I > I

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Solution

The correct option is B $I > I I I > I I$
As molecular hydrogen has its fulfilled duplete so it is stable. All other forms are unstable due to presence of single electron so they are more reacting and better reducing agent.
So, order of reactivity is $I > I I I > I I$ .

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The correct order of reactivity among I (atomic hydrogen), II (dihydrogen) and III (nascent hydrogen) is:

The correct option is B I>III>IIAs molecular hydrogen has its fulfilled duplete so it is stable. All other forms are unstable due to presence of single electron so they are more reacting and better reducing agent. So, order of reactivity is I>III>II.

The correct option is B $I > I I I > I I$
As molecular hydrogen has its fulfilled duplete so it is stable. All other forms are unstable due to presence of single electron so they are more reacting and better reducing agent.
So, order of reactivity is $I > I I I > I I$ .