The correct order of reactivity of PhMgBr with following compounds will be: (1).(C6H5)2CO,(2).CH3−CH=O,(3).(CH3)2C=O
A
1>2>3
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B
2>3>1
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C
3>2>1
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D
1>3>2
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Solution
The correct option is B2>3>1 As the positive charge decreases and steric hinderance increases on carbonyl group, the rate of nucleophilic addition reaction decreases.