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Question

The correct order of second ionization enthalpy of C,N,O and F :

A
C>N>O>F
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B
O>N>F>C
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C
O>F>N>C
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D
F>O>N>C
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Solution

The correct option is C O>F>N>C
Electronic configuration of;
8O1s22s22p4
9F1s22s22p5
7N1s22s22p3
6C1s22s22p2
2ndIEO1s22s22p3
F1s22s22p4
N1s22s22p2
C1s22s22p1
Oxygen having half filled configuration is most stable and will require high energy to remove an e. Followed by fluorine being the most electronegative element, then followed by N which is less electronegative than F but more than C.
Order of second ionization enthalpy is O>F>N>C

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