The correct order of size would be:

N i < P d < P t

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P d < P t < N i

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P t > N i > P d

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P d > P t > N i

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Solution

The correct option is A $N i < P d < P t$
The correct order of size would be $N i < P d < P t$ .
In a group, on moving down from top to bottom, the ionic radius increases.
Hence, $N i < P d$
Also due to lanthanoid contraction $P d < P t$ .

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