Question

The correct order of solubility of isomeric alcohols in water is.

• A. $3^{\circ }>2^{\circ }>1^{\circ }$
• B. $1^{\circ }>2^{\circ }>3^{\circ }$
• C. $3^{\circ }>1^{\circ }>2^{\circ }$
• D. $2^{\circ }>1^{\circ }>3^{\circ }$

Answer 1

The correct option is A $3^{\circ }>2^{\circ }>1^{\circ }$

• Alcohols are soluble in water because they form intermolecular hydrogen bonding with water molecules. The solubility decreases with an increase in mass because the hydrocarbon part becomes larger and resists the formation of hydrogen bonds with water molecules.
• The solubility of isomeric alcohols increases with branching because the surface area of the hydrocarbon part decreases with branching.

Hence The correct order of solubility of isomeric alcohols in water is $3^0>2^0>1^0.$

option A is the correct answer.